(1/x-2)+(1/x-2)=(14/x^2-4)

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Solution for (1/x-2)+(1/x-2)=(14/x^2-4) equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x+1/x-2-2 = 14/(x^2)-4 // - 14/(x^2)-4

1/x+1/x-(14/(x^2))-2-2+4 = 0

1/x+1/x-14*x^-2-2-2+4 = 0

2*x^-1-14*x^-2 = 0

t_1 = x^-1

2*t_1^1-14*t_1^2 = 0

2*t_1-14*t_1^2 = 0

DELTA = 2^2-(-14*0*4)

DELTA = 4

DELTA > 0

t_1 = (4^(1/2)-2)/(-14*2) or t_1 = (-4^(1/2)-2)/(-14*2)

t_1 = 0 or t_1 = 1/7

t_1 = 0

x^-1+0 = 0

x^-1 = 0

1*x^-1 = 0 // : 1

x^-1 = 0

x naleu017Cy do O

t_1 = 1/7

x^-1-1/7 = 0

1*x^-1 = 1/7 // : 1

x^-1 = 1/7

-1 < 0

1/(x^1) = 1/7 // * x^1

1 = 1/7*x^1 // : 1/7

7 = x^1

x = 7

x = 7

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